If a base load is 30 cubic yards and material expands by 25%, what is the expanded volume per load?

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Multiple Choice

If a base load is 30 cubic yards and material expands by 25%, what is the expanded volume per load?

Explanation:
To determine the expanded volume per load when a base load is subject to a 25% expansion, one must first understand how to compute the increase in volume. Starting with a base load of 30 cubic yards, if this volume expands by 25%, the calculation involves finding 25% of 30 cubic yards and then adding this amount back to the original volume. First, calculate 25% of the base load: \[ 25\% \text{ of } 30 = \frac{25}{100} \times 30 = 7.5 \text{ cubic yards} \] Next, add this expansion amount to the original volume: \[ \text{Expanded Volume} = \text{Base Load} + \text{Expanded Amount} = 30 + 7.5 = 37.5 \text{ cubic yards} \] Thus, the expanded volume per load, considering the 25% increase, is 37.5 cubic yards. This logic helps clarify why the correct answer is represented by that specific choice, demonstrating the straightforward approach of calculating a percentage increase based directly on the initial value.

To determine the expanded volume per load when a base load is subject to a 25% expansion, one must first understand how to compute the increase in volume.

Starting with a base load of 30 cubic yards, if this volume expands by 25%, the calculation involves finding 25% of 30 cubic yards and then adding this amount back to the original volume.

First, calculate 25% of the base load:

[

25% \text{ of } 30 = \frac{25}{100} \times 30 = 7.5 \text{ cubic yards}

]

Next, add this expansion amount to the original volume:

[

\text{Expanded Volume} = \text{Base Load} + \text{Expanded Amount} = 30 + 7.5 = 37.5 \text{ cubic yards}

]

Thus, the expanded volume per load, considering the 25% increase, is 37.5 cubic yards. This logic helps clarify why the correct answer is represented by that specific choice, demonstrating the straightforward approach of calculating a percentage increase based directly on the initial value.

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